How can i convert the Gemini-API response into the JSON struxture
the Gemini-pro-vision response type is
{
"title": "Black Tissue Box",
"description": "A black tissue box that is perfect for any room in your home.",
"category": "Home Decor",
"estimatedPrice": 10.99
}
<class 'str'>
What I realize I need to make my own for the use case
Solved! Go to Solution.
To convert the Gemini-API response into the desired JSON structure, you need to parse the string response and then convert it into a JSON object. In Python, this can be achieved using the json module. Here’s how you can do it:
Here's a string response from the Gemini-API:
response_str = '{"title": "Black Tissue Box", "description": "A black tissue box that is perfect for any room in your home.", "category": "Home Decor", "estimatedPrice": 10.99}'
Here’s a step-by-step guide to parse this into a JSON structure:
response_json = json.dumps(response_dict, indent=2)
print(response_json)
If the response string is coming from an API call directly, you might not need to convert it to a string first. It could already be in a dictionary format.
Always ensure that the response string is properly formatted JSON. If not, you'll need to handle possible exceptions using try-except blocks.
To convert the Gemini-API response into the desired JSON structure, you need to parse the string response and then convert it into a JSON object. In Python, this can be achieved using the json module. Here’s how you can do it:
Here's a string response from the Gemini-API:
response_str = '{"title": "Black Tissue Box", "description": "A black tissue box that is perfect for any room in your home.", "category": "Home Decor", "estimatedPrice": 10.99}'
Here’s a step-by-step guide to parse this into a JSON structure:
response_json = json.dumps(response_dict, indent=2)
print(response_json)
If the response string is coming from an API call directly, you might not need to convert it to a string first. It could already be in a dictionary format.
Always ensure that the response string is properly formatted JSON. If not, you'll need to handle possible exceptions using try-except blocks.
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