Hi,
How to make in a form to fill an image type column with a URL instead of the local file browser?
Not finding how to do it just from a column of type image, I tried to create a column of type URL to fill a virtual column of type show (image). I tried different formulas, but I can't convert the url to image.
Could you please help me ?
Solved! Go to Solution.
I found a very simple solution:
- I used a URL type column named [PictureURL] which is only displayed in forms.
- Then I created a column of type show (image) using this very simple formula:
TEXT([PictureURL])
@Bulubulu wrote:
I tried to create a column of type URL to fill a virtual column of type show (image)
That's what I would have tried too.
@Bulubulu wrote:
I tried different formulas
If you didn't already, maybe fiddle with including HYPERLINK() -- or even LINK(HYPERLINK()) -- somewhere in the mix.
THANKS ! I do not know how. It seems to me that these functions would be rather useful for the reverse operation (converting an image to a URL). What I'm looking for would rather be an equivalent of the IMAGE() function in Google Sheets.
Yes, I agree. Given that you already tried what seemed most logical to both you and me, my suggestion was to experiment with an alternate approach.
I found a very simple solution:
- I used a URL type column named [PictureURL] which is only displayed in forms.
- Then I created a column of type show (image) using this very simple formula:
TEXT([PictureURL])
I don't know if it is what you are looking for but try using a Longtext type column with HTML format and use in the formula:
"<img src=' "&[URL]&" ' width=100%>"
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