Start View with a click of Buttons

[Rehan_A_Khan]

I am Trying to create a Menu with Buttons like
Created a new View for this in the View name of Menu List with Buttons Like to start other Views with click of these Buttons.
The View of these buttons is Gallery Type and Table is also attached to display these buttons.
I don't know how to link the forms with these Buttons.
I am try to Linktoview() but couldn't succeed.
But I don't want to use App url http ://

https://www.appsheet.com/start/2278438b-c90f-4642-91bb-a3a26a31a9d2#view=Exhibition

Like to use Linktoview() option so that quickly change/switch to that view, the http: option reload the application and form , takes time to load.

Pls. help me.
I have attached the photos.

 

 

 

[Izzat_Safrah]

Try this in Action/Target

Do This 

 App: go to another view within app 

Target 

LINKTOFILTEREDVIEW(“Name_View_A”, [Columns_In_View_A] = [_THISROW].[Columns_In_This_Table])

Table_1

Item No_1	Name
88	Chair
89	Books

Table_2

Item No_2	Name	Color	Pcs
88	Chair	White	5
88	Chair	Blue	10
89	Books	White	1
89	Books	Blue	20
89	Books	Red	30

LINKTOFILTEREDVIEW(“STOCK”, [ITEM NO_2] = [_THISROW].[ITEM NO_1])

View ( STOCK ) used table name ( Table_2 )

[Rehan_A_Khan]

thanks,
But Actually, I have lot of Views in my Menus, So I want some of them to be in one screen,
Thats why I create some buttons and wants to attached these views with these buttons.

With your soluion, It works with data , but didn't call the new view as per my requirement.

I want to create Behavior to connect with buttons simply to open a new View (predefined already).

[Izzat_Safrah]

You don't want the column name [Link] in your table. Just use the column [Menu]  for your buttons

1- Creat a new action 

Do This   App: go to another view within app 

Target      LINKTOVIEW([Menu])

2- Go to your view