Can you give me the formula of this logic and i can structure it by using your way. Logic: Virtual column needs to add itself number "10" eachday without losing its previous value. and minus ( sum of this column: [ Expenses] (which contains daily expenses). If today's all expenses sum value is 5 then show me Today: 5 (bcs 10-5), Tomorrow: 15 (5+10), Aftermorrow: 25 and etc. Mine is losing its previous value and calculating the formula again. Please reply.
2) Btw how i can add number 3 to this column (contains this formula) not to expenses column (i can add expense form another table). If i add this 3 to this formula by doing arithmetic, it will calculate this everday but i need to add this 3 for one beggining time that's it.
Showing error, [Date] is the type of Datetime which is showing current date and time with formula (live). What's the problem sir?
In my previous reply, I overlooked that you need to convert the duration value that results from TODAY () - [Date]
into a number value quantifying the days or hours or whatever you need. See explanation and examples in Date and time expressions - AppSheet Help. For instance:
HOUR(TODAY() - [TargetDate]) / 24
: number of days between today's date and the Date
value given in the TargetDate
column.BTW, Ўзбекмисиз?
I am sorry but i didn't have another choice, none is replying even reading while others has been replied too many times in a few minutes. Sry sir
FYI, replies are frequently not immediate.
I'm not sure what you thought would happen by repeatedly posting your question, but I doubt it increases the likelihood of receiving an answer.
Can you help me with that please
Please do not reply if you cannot help until the problem is resolved
User | Count |
---|---|
16 | |
10 | |
9 | |
8 | |
3 |