Subtract lists to produce another containing only the unique items of the first list that aren't also in the second

I donโ€™t know anymore what formula to use to get this to work. What I want is from a list() group - the list() column will return the remainder of the right-hand side list.

it doesnโ€™t work like this photo Iโ€™m showing,

can someone help me???

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13 REPLIES 13

Steve
Platinum 5
Platinum 5

Original post:

Steve
Platinum 5
Platinum 5

For reference:

Steve
Platinum 5
Platinum 5

Please post a screenshot of the complete expression youโ€™re using.

Please advise

Have you used Test to confirm your expression produces the expected results?

3X_0_3_037c0e8b2b563e298c2f578b33de5fed839fe5c9.png

3X_2_7_27bf1eab5849edd6bcaee0816e6fca9314ced691.png

Yes, I have used testโ€ฆ
but the results are not as expected.

for with one item, like screenshot โ€œJanโ€ can work, but with reduction Jan,Feb,Mar

Reduction doesnโ€™t work

Wrap your SELECT() expression with CONCATENATE() and SPLIT():

SPLIT(CONCATENATE(SELECT(...)), " , ")

See also:

it works @Steveโ€ฆ
thank you,

I had thought about using split, but was confused about how to combine it.

Could you check this anyway? Just to make sure we are not fixing a problem made initialy by changing the Item separator so that others could avoid it in the future

like this

Thanks.
Seems like Item separator is "," instead of " , "

Please post your [Pembayaran Bulan] config.
Like this:

Seems like you were playing with the Item separator. By default it is " , ". Leave it as default

Good point!