Url field type

Hi. I am trying to get the url field type working. I have a table called Product_Master_File which has a column [Cubic Metres]. When adding a product not everyone will know the cubic metre value so I have added a virtual column, type url. I have another table called External_Links_Index with 2 columns i.e. [Url] & [Link Text]. So i want to use the app formula in the VC to pull out a specific row and make it a url link to the Cubic Metre Calculator Google Sheet.

I have something like this so far but it is returning a null value.

HYPERLINK(
ANY(SELECT(External_Links_Index[Url],CONTAINS([Url],1019016821))),
โ€œCubic Metres Calculationโ€)

The number in the CONTAINS part of the expression being the id of the tab in the google sheet. Am I on the right track here. Any help would be great, thank you.

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1 ACCEPTED SOLUTION

For the Cubic Metres Calculation column:

  1. Change the column type to Show.
  2. Set the Category to Url.
  3. Copy the current app formula to Content.
  4. Set App formula to "".

The reason youโ€™re getting the current behavior is because youโ€™re in a form. Forms exist to allow the user to edit column values, so the form is presenting the column value for editing. But Url column types arenโ€™t editable (for some reason, perhaps because they could have both link and label components), so the value is grayed-out. You want to present the value as a navigation element, not as an editable field, which is what the Show column type Url category is for.

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